If 5 unicast channels are sent between two devices at a sample rate of 48KHz and 24-bit, what is the total bandwidth used?

To determine the total bandwidth used by 5 unicast channels at a sample rate of 48 kHz and a bit depth of 24 bits, it's important to first calculate the bandwidth required per channel and then multiply it by the number of channels.

The formula to calculate the bandwidth per channel is:

[ \text{Bandwidth per channel} = \text{Sample Rate} \times \text{Bit Depth} \times \text{Number of Channels} ]

Since we are interested in the total bandwidth for all channels, we will consider the following:

1. Sample Rate: 48,000 samples per second (48 kHz).
2. Bit Depth: 24 bits per sample.
3. Number of Channels: 5 unicast channels.

Now, let's compute the bandwidth for one channel:

[ \text{Bandwidth per channel} = 48,000 , \text{samples/second} \times 24 , \text{bits/sample} = 1,152,000 , \text{bits/second} , (or , 1.152 , Mbps) ]

Now, to find the total bandwidth for 5 channels:

[