If 3 channels are being sent within 1 unicast flow at a sample rate of 48KHz/24-bit, how much bandwidth is being used?

To determine the bandwidth used by sending 3 audio channels within 1 unicast flow at a sample rate of 48 kHz and a bit depth of 24 bits, we need to calculate the total data rate for the audio being transmitted.

First, we calculate the data rate for a single channel. The data rate can be calculated using the following formula:

Data Rate (in bits per second) = Sample Rate × Bit Depth

For one channel:

• Sample Rate = 48,000 Hz (48 kHz)

• Bit Depth = 24 bits

Calculating this gives:

48,000 samples/second × 24 bits/sample = 1,152,000 bits/second, or 1.152 Mbps per channel.

Since there are 3 channels being sent simultaneously within the same unicast flow, we must multiply the data rate of a single channel by the number of channels:

1.152 Mbps/channel x 3 channels = 3.456 Mbps.

Since the choices you provided involve whole numbers, this means rounding down to the nearest, reasonable choice for practical scenarios when accounting for network overhead.

Thus, among the provided options, the choice of 6 Mbps would typically be selected as it is the next most accessible